LaTeX 分行調試

於 Spectrum 看到有人問如何在 Academic 中幫 LaTeX 排版，在官方文檔中其實有提及有關方法，但自己也花了些時間才弄清楚，特此記錄解決方法：

\begin{align}
    \begin{aligned}
        2x+3 &= 7 & (2x+3-3 &= 7-3) \\
        2x &= 4 & (\frac{2x}2 &= \frac42)\\
        x &= 2
    \end{aligned}
\end{align}

\begin{align} \begin{aligned} 2x+3 &= 7 & (2x+3-3 &= 7-3) \
2x &= 4 & (\frac{2x}2 &= \frac42)\
x &= 2 \end{aligned} \end{align}

\begin{align}
    \begin{aligned}
        2x+3 &= 7 & (2x+3-3 &= 7-3) \\\\
        2x &= 4 & (\frac{2x}2 &= \frac42)\\\\
        x &= 2
    \end{aligned}
\end{align}

\begin{align} \begin{aligned} 2x+3 &= 7 & (2x+3-3 &= 7-3) \\
2x &= 4 & (\frac{2x}2 &= \frac42)\\
x &= 2 \end{aligned} \end{align}